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Ch.13 - Solutions & Their Properties
Chapter 13, Problem 7

A 10.0 M aqueous solution of NaOH has a density of 1.33 g/cm3 at 25 C. Calculate the mass percent of the NaOH in the solution (a) 53.2% (b) 30.1% (c) 40.0% (d) 13.3%

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Molarity

Molarity (M) is a measure of concentration defined as the number of moles of solute per liter of solution. In this question, the 10.0 M NaOH solution indicates that there are 10 moles of NaOH in every liter of the solution. Understanding molarity is crucial for calculating the mass of solute present in a given volume of solution.
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Density

Density is the mass of a substance per unit volume, typically expressed in grams per cubic centimeter (g/cm³). The density of the NaOH solution is given as 1.33 g/cm³, which allows us to convert the volume of the solution into mass. This conversion is essential for determining the mass percent of NaOH in the solution.
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Mass Percent

Mass percent is a way of expressing the concentration of a component in a mixture, calculated as the mass of the solute divided by the total mass of the solution, multiplied by 100. To find the mass percent of NaOH, we need to calculate the mass of NaOH in the solution and the total mass of the solution, which includes both the solute and the solvent.
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The molarity of a solution of sodium acetate (CH3COONa) at 20 C is 7.5 M. Use the graph showing the solubility of sodium acetate as a function of temperature to describe the solution. The solution is . (LO 13.7, 13.8)

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