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Ch.14 - Chemical Kinetics
Chapter 14, Problem 76

Consider this overall reaction, which is experimentally observed to be second order in X and first order in Y: X + Y → XY. a. Does the reaction occur in a single step in which X and Y collide? b. Is this two-step mechanism valid? 2X →k1/k2 X2 (Fast) X2 + Y →k3 XY + X (Slow)

Verified step by step guidance
1
<Step 1: Understand the reaction order.> The reaction is given as second order in X and first order in Y. This means the rate law is rate = k[X]^2[Y].
<Step 2: Analyze the possibility of a single-step mechanism.> For a reaction to occur in a single step, the molecularity must match the reaction order. Here, the reaction order is third (2 in X and 1 in Y), which suggests a termolecular process. Termolecular reactions are rare due to the low probability of three molecules colliding simultaneously with the correct orientation and energy.
<Step 3: Evaluate the proposed two-step mechanism.> The mechanism consists of two steps: (1) 2X → X2 (fast) and (2) X2 + Y → XY + X (slow).
<Step 4: Determine the rate-determining step.> The slow step (step 2) is the rate-determining step. The rate law for this step is rate = k3[X2][Y].
<Step 5: Relate the mechanism to the observed rate law.> From step 1, X2 is formed quickly and is in equilibrium with 2X. Therefore, [X2] can be expressed in terms of [X] using the equilibrium constant for the fast step. Substitute [X2] in the rate law of the slow step to see if it matches the observed rate law rate = k[X]^2[Y]. If it does, the mechanism is valid.>

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Reaction Order

Reaction order refers to the power to which the concentration of a reactant is raised in the rate law of a chemical reaction. It provides insight into the relationship between the concentration of reactants and the rate of the reaction. In this case, the reaction is second order in X and first order in Y, indicating that the rate depends quadratically on the concentration of X and linearly on the concentration of Y.
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Mechanism of Reaction

The mechanism of a reaction describes the step-by-step sequence of elementary reactions by which overall chemical change occurs. Understanding the mechanism helps in determining how reactants are converted to products, including whether the reaction occurs in a single step or multiple steps. The proposed two-step mechanism suggests that the first step is fast and reversible, while the second step is slow and rate-determining.
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Elementary Steps and Rate-Determining Step

Elementary steps are individual reactions that make up the overall reaction mechanism. The rate-determining step is the slowest step in the mechanism, which controls the overall reaction rate. In the provided mechanism, the second step is the slow step, making it the rate-determining step, which aligns with the observed reaction orders and helps validate the proposed mechanism.
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