Name each compound in which the benzene ring is best treated as a substituent. b.

Video transcript

Hello everyone today. We are being told that benzene is treated as a substitute in the compound below. And to give the name of said compound. So the first thing I wanna do is we want to identify a parent chain and that is simply the longest carbon chain that there is. And so we can either start With this ring and we can go around, we can go 123456. Or we can start from this linear chain and we can go 12345. We're going to continue going to the left because there are more carbons. If we go to the left then if we were to go up or down and then at the sixth carbon we can either go to the left or we can go up if we go up we have an additional two carbons versus going to the left, which would only give us one additional carbon. With this numbering system. We can see that there are more chains or more carbons in this linear chain giving us a parent name of art. We have to denote if there is an al keen or a double bond within this group. Seeing that there is one between carbons three and four. We can go ahead and make this into an octane that E N E is for when there is an alkaline or a double bond. The next step is to identify any substitue ints that maybe there so we can identify any substitutes that are there. And so the substitution is essentially any group that is not attached to the parent chain. And so in labeling our substitue ints we see that we have this final group or this benzene group And we see that we also have one method on carbon five. Another method on carbon five and a method on carbon six. Therefore we have the following substitue ints we have a two fennel since we have a final group at the second carbon And then we have what looks like 556 try methyl Tri means three. Methyl is to denote the methyl groups that we have. And so the third step is to put this all together. And so we want to do that in alphabetical order. And so when determining to go between these two substitue ints we have to look at this fennel, this P and fennel and we have to look at this M in methyl when there is a prefix that denotes the quantity of a substitute, we just ignore it. And so m comes before P in the Alphabet. So we're going to say that this is tri Methyl two fennel. And before we put our parent chain at the end we have to do you know where that double bond is to let us know that this is an alkaline. And so we can just go ahead and put that between Carbons three and 4, we're going to pick the lower number. So carbon three. So we can say two final 3 dash teen as our final answer. I hope this helped, and until next time.