03:53Determine if an Equation is a Hyperbola, Ellipse, Parabola or CircleMario's Math Tutoring314views
Multiple ChoiceGraph the parabola −4(y+1)=(x+1)2-4\left(y+1\right)=\left(x+1\right)^2−4(y+1)=(x+1)2, and find the focus point and directrix line.142viewsHas a video solution.
Multiple ChoiceIf a parabola has the focus at (0,−1)\left(0,-1\right)(0,−1) and a directrix line y=1y=1y=1, find the standard equation for the parabola.132viewsHas a video solution.
Multiple ChoiceGraph the parabola 8(x+1)=(y−2)28\left(x+1\right)=\left(y-2\right)^28(x+1)=(y−2)2 , and find the focus point and directrix line.111viewsHas a video solution.
Multiple ChoiceIf a parabola has the focus at (2,4)\left(2,4\right)(2,4) and a directrix line x=−4x=-4x=−4 , find the standard equation for the parabola.103viewsHas a video solution.
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. x^2 - 4x - 2y = 0231viewsHas a video solution.
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (12,0); Directrix: x=-12413viewsHas a video solution.
Textbook QuestionIdentify the conic represented by the equation without completing the square. 4x^2 - 9y^2 - 8x + 12y - 144 = 0604viewsHas a video solution.
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)343viewsHas a video solution.
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01298viewsHas a video solution.
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x460viewsHas a video solution.
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)343viewsHas a video solution.
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01298viewsHas a video solution.
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x460viewsHas a video solution.
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)343viewsHas a video solution.
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11650viewsHas a video solution.
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 8x318viewsHas a video solution.
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x460viewsHas a video solution.
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11650viewsHas a video solution.
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = 4x126viewsHas a video solution.
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = 4y162viewsHas a video solution.
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = - 4y180viewsHas a video solution.
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x148viewsHas a video solution.
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x148viewsHas a video solution.
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 16x108viewsHas a video solution.
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = - 8x123viewsHas a video solution.
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = 12y123viewsHas a video solution.
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = - 16y132viewsHas a video solution.
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0156viewsHas a video solution.
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0156viewsHas a video solution.
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. 8x^2 + 4y = 0161viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (7, 0); Directrix: x = - 7407viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 5, 0); Directrix: x = 5160viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15173viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15173viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25150viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25150viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)202viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)202viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)202viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (3, 2); Directrix: x = - 1203viewsHas a video solution.
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 3, 4); Directrix: y = 2142viewsHas a video solution.
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = 4(x - 1)155viewsHas a video solution.
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (x + 1)^2 = - 4(y + 1)149viewsHas a video solution.
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = - 4(x - 1)153viewsHas a video solution.
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)136viewsHas a video solution.
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)136viewsHas a video solution.
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x + 1)^2 = - 8(y + 1)96viewsHas a video solution.
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 3)^2 = 12(x + 1)110viewsHas a video solution.
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 1)^2 = - 8x115viewsHas a video solution.
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 - 2x - 4y + 9 =0118viewsHas a video solution.
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. y^2 - 2y + 12x - 35 = 0164viewsHas a video solution.
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 + 6x - 4y + 1 = 0116viewsHas a video solution.
Textbook QuestionIn Exercises 49–56, identify each equation without completing the square. y^2 - 4x + 2y + 21 = 0184viewsHas a video solution.
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0237viewsHas a video solution.
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0237viewsHas a video solution.
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3150viewsHas a video solution.
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3150viewsHas a video solution.
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3150viewsHas a video solution.
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? x = - 4(y - 1)^2 + 3169viewsHas a video solution.
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. (y - 2)^2 = x + 4 y = - (1/2)x108viewsHas a video solution.
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = y^2 - 3 x = y^2 - 3y131viewsHas a video solution.
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = (y + 2)^2 - 1 (x - 2)^2 + (y + 2)^2 = 1182viewsHas a video solution.