03:53Determine if an Equation is a Hyperbola, Ellipse, Parabola or CircleMario's Math Tutoring537views
Multiple ChoiceGraph the parabola −4(y+1)=(x+1)2-4\left(y+1\right)=\left(x+1\right)^2−4(y+1)=(x+1)2, and find the focus point and directrix line.247views
Multiple ChoiceIf a parabola has the focus at (0,−1)\left(0,-1\right)(0,−1) and a directrix line y=1y=1y=1, find the standard equation for the parabola.228views
Multiple ChoiceGraph the parabola 8(x+1)=(y−2)28\left(x+1\right)=\left(y-2\right)^28(x+1)=(y−2)2 , and find the focus point and directrix line.224views
Multiple ChoiceIf a parabola has the focus at (2,4)\left(2,4\right)(2,4) and a directrix line x=−4x=-4x=−4 , find the standard equation for the parabola.165views1rank
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. x^2 - 4x - 2y = 0438views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (12,0); Directrix: x=-12568views
Textbook QuestionIdentify the conic represented by the equation without completing the square. 4x^2 - 9y^2 - 8x + 12y - 144 = 0745views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)540views
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01497views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x731views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)540views
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01497views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x731views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)540views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11867views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 8x542views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x731views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11867views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = 4x255views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = 4y269views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = - 4y372views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x236views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x236views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 16x172views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = - 8x183views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = 12y244views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = - 16y204views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0298views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0298views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. 8x^2 + 4y = 0271views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (7, 0); Directrix: x = - 7547views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 5, 0); Directrix: x = 5254views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15241views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15241views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25221views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25221views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)284views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)284views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)284views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (3, 2); Directrix: x = - 1303views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 3, 4); Directrix: y = 2198views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = 4(x - 1)273views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (x + 1)^2 = - 4(y + 1)231views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = - 4(x - 1)233views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)271views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)271views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x + 1)^2 = - 8(y + 1)182views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 3)^2 = 12(x + 1)184views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 1)^2 = - 8x215views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 - 2x - 4y + 9 =0224views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. y^2 - 2y + 12x - 35 = 0297views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 + 6x - 4y + 1 = 0184views
Textbook QuestionIn Exercises 49–56, identify each equation without completing the square. y^2 - 4x + 2y + 21 = 0283views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0338views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0338views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3222views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3222views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3222views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? x = - 4(y - 1)^2 + 3239views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. (y - 2)^2 = x + 4 y = - (1/2)x169views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = y^2 - 3 x = y^2 - 3y201views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = (y + 2)^2 - 1 (x - 2)^2 + (y + 2)^2 = 1318views
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