03:53Determine if an Equation is a Hyperbola, Ellipse, Parabola or CircleMario's Math Tutoring429views
Multiple ChoiceGraph the parabola −4(y+1)=(x+1)2-4\left(y+1\right)=\left(x+1\right)^2−4(y+1)=(x+1)2, and find the focus point and directrix line.203views
Multiple ChoiceIf a parabola has the focus at (0,−1)\left(0,-1\right)(0,−1) and a directrix line y=1y=1y=1, find the standard equation for the parabola.191views
Multiple ChoiceGraph the parabola 8(x+1)=(y−2)28\left(x+1\right)=\left(y-2\right)^28(x+1)=(y−2)2 , and find the focus point and directrix line.176views
Multiple ChoiceIf a parabola has the focus at (2,4)\left(2,4\right)(2,4) and a directrix line x=−4x=-4x=−4 , find the standard equation for the parabola.136views1rank
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. x^2 - 4x - 2y = 0325views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (12,0); Directrix: x=-12497views
Textbook QuestionIdentify the conic represented by the equation without completing the square. 4x^2 - 9y^2 - 8x + 12y - 144 = 0678views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)441views
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01373views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x594views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)441views
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01373views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x594views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)441views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11777views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 8x432views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x594views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11777views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = 4x171views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = 4y224views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = - 4y280views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x192views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x192views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 16x141views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = - 8x154views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = 12y169views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = - 16y173views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0233views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0233views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. 8x^2 + 4y = 0225views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (7, 0); Directrix: x = - 7482views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 5, 0); Directrix: x = 5207views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15207views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15207views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25184views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25184views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)239views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)239views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)239views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (3, 2); Directrix: x = - 1256views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 3, 4); Directrix: y = 2174views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = 4(x - 1)230views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (x + 1)^2 = - 4(y + 1)195views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = - 4(x - 1)200views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)209views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)209views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x + 1)^2 = - 8(y + 1)141views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 3)^2 = 12(x + 1)149views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 1)^2 = - 8x165views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 - 2x - 4y + 9 =0178views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. y^2 - 2y + 12x - 35 = 0236views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 + 6x - 4y + 1 = 0153views
Textbook QuestionIn Exercises 49–56, identify each equation without completing the square. y^2 - 4x + 2y + 21 = 0235views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0290views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0290views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3189views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3189views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3189views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? x = - 4(y - 1)^2 + 3207views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. (y - 2)^2 = x + 4 y = - (1/2)x137views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = y^2 - 3 x = y^2 - 3y169views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = (y + 2)^2 - 1 (x - 2)^2 + (y + 2)^2 = 1271views
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