03:53Determine if an Equation is a Hyperbola, Ellipse, Parabola or CircleMario's Math Tutoring522views
Multiple ChoiceGraph the parabola −4(y+1)=(x+1)2-4\left(y+1\right)=\left(x+1\right)^2−4(y+1)=(x+1)2, and find the focus point and directrix line.239views
Multiple ChoiceIf a parabola has the focus at (0,−1)\left(0,-1\right)(0,−1) and a directrix line y=1y=1y=1, find the standard equation for the parabola.221views
Multiple ChoiceGraph the parabola 8(x+1)=(y−2)28\left(x+1\right)=\left(y-2\right)^28(x+1)=(y−2)2 , and find the focus point and directrix line.207views
Multiple ChoiceIf a parabola has the focus at (2,4)\left(2,4\right)(2,4) and a directrix line x=−4x=-4x=−4 , find the standard equation for the parabola.156views1rank
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. x^2 - 4x - 2y = 0418views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (12,0); Directrix: x=-12550views
Textbook QuestionIdentify the conic represented by the equation without completing the square. 4x^2 - 9y^2 - 8x + 12y - 144 = 0731views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)526views
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01472views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x708views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)526views
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01472views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x708views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)526views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11855views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 8x519views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x708views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11855views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = 4x248views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = 4y259views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = - 4y359views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x229views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x229views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 16x164views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = - 8x175views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = 12y233views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = - 16y194views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0288views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0288views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. 8x^2 + 4y = 0263views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (7, 0); Directrix: x = - 7535views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 5, 0); Directrix: x = 5246views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15230views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15230views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25215views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25215views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)274views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)274views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)274views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (3, 2); Directrix: x = - 1292views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 3, 4); Directrix: y = 2191views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = 4(x - 1)264views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (x + 1)^2 = - 4(y + 1)224views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = - 4(x - 1)227views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)261views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)261views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x + 1)^2 = - 8(y + 1)174views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 3)^2 = 12(x + 1)174views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 1)^2 = - 8x204views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 - 2x - 4y + 9 =0212views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. y^2 - 2y + 12x - 35 = 0286views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 + 6x - 4y + 1 = 0177views
Textbook QuestionIn Exercises 49–56, identify each equation without completing the square. y^2 - 4x + 2y + 21 = 0271views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0332views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0332views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3212views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3212views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3212views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? x = - 4(y - 1)^2 + 3233views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. (y - 2)^2 = x + 4 y = - (1/2)x161views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = y^2 - 3 x = y^2 - 3y192views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = (y + 2)^2 - 1 (x - 2)^2 + (y + 2)^2 = 1305views
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