03:53Determine if an Equation is a Hyperbola, Ellipse, Parabola or CircleMario's Math Tutoring358views
Multiple ChoiceGraph the parabola −4(y+1)=(x+1)2-4\left(y+1\right)=\left(x+1\right)^2−4(y+1)=(x+1)2, and find the focus point and directrix line.160views
Multiple ChoiceIf a parabola has the focus at (0,−1)\left(0,-1\right)(0,−1) and a directrix line y=1y=1y=1, find the standard equation for the parabola.150views
Multiple ChoiceGraph the parabola 8(x+1)=(y−2)28\left(x+1\right)=\left(y-2\right)^28(x+1)=(y−2)2 , and find the focus point and directrix line.134views
Multiple ChoiceIf a parabola has the focus at (2,4)\left(2,4\right)(2,4) and a directrix line x=−4x=-4x=−4 , find the standard equation for the parabola.115views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. x^2 - 4x - 2y = 0258views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (12,0); Directrix: x=-12449views
Textbook QuestionIdentify the conic represented by the equation without completing the square. 4x^2 - 9y^2 - 8x + 12y - 144 = 0635views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)381views
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01329views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x511views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)381views
Textbook QuestionIdentify the conic represented by the equation without completing the square. y^2 + 4x + 2y - 15 = 01329views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x511views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (x-4)^2 = 4(y+1)381views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11706views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 8x372views
Textbook QuestionFind the vertex, focus, and directrix of the parabola with the given equation. Then graph the parabola. (y-2)^2 = -16x511views
Textbook QuestionFind the standard form of the equation of the parabola satisfying the given conditions. Focus: (0,-11); Directrix: y=11706views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = 4x136views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = 4y189views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). x^2 = - 4y216views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x160views
Textbook QuestionIn Exercises 1–4, find the focus and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). y^2 = - 4x160views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = 16x117views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 = - 8x135views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = 12y135views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. x^2 = - 16y144views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0183views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. y^2 - 6x = 0183views
Textbook QuestionIn Exercises 5–16, find the focus and directrix of the parabola with the given equation. Then graph the parabola. 8x^2 + 4y = 0186views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (7, 0); Directrix: x = - 7432views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 5, 0); Directrix: x = 5175views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15184views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, 15); Directrix: y = - 15184views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25161views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (0, - 25); Directrix: y = 25161views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)215views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)215views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Vertex: (2, - 3); Focus: (2, - 5)215views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (3, 2); Directrix: x = - 1219views
Textbook QuestionIn Exercises 17–30, find the standard form of the equation of each parabola satisfying the given conditions. Focus: (- 3, 4); Directrix: y = 2150views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = 4(x - 1)181views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (x + 1)^2 = - 4(y + 1)166views
Textbook QuestionIn Exercises 31–34, find the vertex, focus, and directrix of each parabola with the given equation. Then match each equation to one of the graphs that are shown and labeled (a)–(d). (y - 1)^2 = - 4(x - 1)171views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)164views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x - 2)^2 = 8(y - 1)164views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (x + 1)^2 = - 8(y + 1)112views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 3)^2 = 12(x + 1)127views
Textbook QuestionIn Exercises 35–42, find the vertex, focus, and directrix of each parabola with the given equation. Then graph the parabola. (y + 1)^2 = - 8x137views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 - 2x - 4y + 9 =0143views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. y^2 - 2y + 12x - 35 = 0188views
Textbook QuestionIn Exercises 43–48, convert each equation to standard form by completing the square on x or y. Then find the vertex, focus, and directrix of the parabola. Finally, graph the parabola. x^2 + 6x - 4y + 1 = 0129views
Textbook QuestionIn Exercises 49–56, identify each equation without completing the square. y^2 - 4x + 2y + 21 = 0198views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0250views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y^2 + 6y - x + 5 = 0250views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3162views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3162views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? y = - x^2 + 4x - 3162views
Textbook QuestionIn Exercises 57–62, use the vertex and the direction in which the parabola opens to determine the relation's domain and range. Is the relation a function? x = - 4(y - 1)^2 + 3181views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. (y - 2)^2 = x + 4 y = - (1/2)x117views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = y^2 - 3 x = y^2 - 3y142views
Textbook QuestionIn Exercises 63–68, find the solution set for each system by graphing both of the system's equations in the same rectangular coordinate system and finding points of intersection. Check all solutions in both equations. x = (y + 2)^2 - 1 (x - 2)^2 + (y + 2)^2 = 1214views