Skip to main content
Ch. 4 - Inverse, Exponential, and Logarithmic Functions
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
Chapter 5, Problem 73

Solve each equation. (5/2)x = 4/25

Verified step by step guidance
1
Recognize that the equation is of the form \(\left(\frac{5}{2}\right)^x = \frac{4}{25}\). Our goal is to solve for the exponent \(x\).
Express the right side \(\frac{4}{25}\) as powers of numbers related to the base \(\frac{5}{2}\). Notice that \$4 = 2^2\( and \)25 = 5^2$, so rewrite \(\frac{4}{25}\) as \(\frac{2^2}{5^2}\).
Rewrite the right side as \(\left(\frac{2}{5}\right)^2\). Now the equation looks like \(\left(\frac{5}{2}\right)^x = \left(\frac{2}{5}\right)^2\).
Recognize that \(\frac{2}{5}\) is the reciprocal of \(\frac{5}{2}\), so \(\left(\frac{2}{5}\right)^2 = \left(\frac{5}{2}\right)^{-2}\). Substitute this back into the equation to get \(\left(\frac{5}{2}\right)^x = \left(\frac{5}{2}\right)^{-2}\).
Since the bases are the same and the expressions are equal, set the exponents equal to each other: \(x = -2\). This gives the solution for \(x\).

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
2m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Exponential Equations

Exponential equations involve variables in the exponent position, such as a^x = b. Solving these requires rewriting the equation so that both sides have the same base or applying logarithms to isolate the variable.
Recommended video:
5:47
Solving Exponential Equations Using Logs

Properties of Exponents

Understanding properties like a^(m/n) = (a^m)^(1/n) and (a/b)^x = a^x / b^x helps in rewriting expressions with fractional bases or exponents. These properties allow simplification and comparison of exponential terms.
Recommended video:
Guided course
04:06
Rational Exponents

Logarithms

Logarithms are the inverse operations of exponentials and are used to solve equations where the variable is an exponent. Applying logarithms to both sides helps isolate the exponent and solve for the variable.
Recommended video:
7:30
Logarithms Introduction