Table of contents
- 0. Review of Algebra4h 16m
- 1. Equations & Inequalities3h 18m
- 2. Graphs of Equations43m
- 3. Functions2h 17m
- 4. Polynomial Functions1h 44m
- 5. Rational Functions1h 23m
- 6. Exponential & Logarithmic Functions2h 28m
- 7. Systems of Equations & Matrices4h 6m
- 8. Conic Sections2h 23m
- 9. Sequences, Series, & Induction1h 19m
- 10. Combinatorics & Probability1h 45m
1. Equations & Inequalities
Rational Equations
2:04 minutes
Problem 14
Textbook Question
Textbook QuestionIn Exercises 11–20, write an equation that expresses each relationship. Then solve the equation for y. x varies directly as the cube root of z and inversely as y.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Direct Variation
Direct variation describes a relationship where one variable is a constant multiple of another. In this case, 'x varies directly as the cube root of z' means that if z increases, x increases proportionally, and can be expressed as x = k * (z^(1/3)), where k is a constant.
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Inverse Variation
Inverse variation occurs when one variable increases as another decreases. The phrase 'inversely as y' indicates that as y increases, the value of x decreases. This relationship can be expressed as x = k' / y, where k' is another constant.
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Combining Direct and Inverse Variation
When combining direct and inverse variations, we can express the relationship using both types of variation in a single equation. For the given problem, we can combine the two relationships to form an equation like x = k * (z^(1/3)) / y, which can then be solved for y to find its value in terms of x and z.
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