Graph a line with a slope of 0 that passes through the point ( 3 , − 2 ) \left(3,-2\right) ( 3 , − 2 ) .

Everyone, welcome back. So in this problem, we're gonna graph a line with a slope of 0, that's what we're told, and it also passes to the point 3 comma negative 2. So let's get started. Now we know that the definition of slope is it's the rise over the run. Right? It's the steepness of the line, but we actually already know what that line is. We know that it's just a slope of 0. So it's a steepness of 0, and we also know what the point that it passes through. So rather than having to plug in a bunch of points and figure out a bunch of ordered pairs, we know that this line is gonna pass through this point 3 comma negative 2, and it's gonna have a slope of 0. What does a slope of 0 look like? Well, remember, a slope or a steepness of 0 is a perfectly flat horizontal line. So, basically, we don't have to go and plug in a bunch of points because we know exactly what this line is gonna look like. It's just gonna look like a flat line like this. It's always just going to be here. It's never gonna have a different y value than negative 2, and then it's just gonna go sort of like this from left to right. Alright? So that's a slope of 0, and it passes through this point 3 comma negative 2. So, hopefully, that makes sense. Thanks for watching.

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Graph a line with a slope of 0 that passes through the point ﻿(3,−2)\left(3,-2\right)(3,−2)﻿.

Graph a line with a slope of 0 that passes through the point $\left(3,-2\right)$ .