In Exercises 9–16, find the coordinates of the vertex for the par...

Question

In Exercises 9–16, find the coordinates of the vertex for the parabola defined by the given quadratic function. f(x)=2(x−3)^2+1

Accepted Answer

Hey everyone here we are asked to find the vertex of the parabola which is F. Of X is equal to seven times the quantity of x minus five squared minus three. So to find the vertex, we need to recall the vertex form of a parabola which is F. Of X. Is equal to a times the quantity of x minus H squared plus K. So here we can see that our given equation is already in vertex form. So we can go ahead and compare it directly with our formula to find the vertex. But next we need to recall that the vertex is the point H. K. So we need to find our H. And K terms. So we can see that our age here is this negative five but in the formula H is also negative. So our actual H term is positive five. And next for our K term we have negative three. But in the formula it is positive K. So our K is negative three And therefore we are left with answer choice a with a vertex of 5 -3. Thanks for watching. I hope you found this video helpful and I'll see you again next time.

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In Exercises 9–16, find the coordinates of the vertex for the parabola defined by the given quadratic function. f(x)=2(x−3)^2+1