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Ch. 1 - Equations and Inequalities
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
Chapter 2, Problem 47

Which equation has two real, distinct solutions? Do not actually solve.
A. (3x-4)² = -9 B. (4-7x)² = 0 C. (5x-9)(5x-9) = 0 D. (7x+4)² = 11

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1
Recall that an equation of the form \( (ax + b)^2 = c \) will have two real, distinct solutions if and only if \( c > 0 \). This is because taking the square root of both sides yields two different values, \( \sqrt{c} \) and \( -\sqrt{c} \), when \( c \) is positive.
Analyze option A: \( (3x - 4)^2 = -9 \). Since the right side is negative, \( -9 < 0 \), there are no real solutions because a square cannot equal a negative number in the real number system.
Analyze option B: \( (4 - 7x)^2 = 0 \). Here, \( c = 0 \), so there is exactly one real solution (a repeated root), not two distinct solutions.
Analyze option C: \( (5x - 9)(5x - 9) = 0 \) is equivalent to \( (5x - 9)^2 = 0 \), which again means \( c = 0 \) and only one real solution (a repeated root).
Analyze option D: \( (7x + 4)^2 = 11 \). Since \( 11 > 0 \), this equation will have two real, distinct solutions because the square root of 11 is positive and negative, giving two different values for \( x \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Discriminant and Nature of Solutions

The discriminant of a quadratic equation determines the number and type of solutions. If the discriminant is positive, there are two distinct real solutions; if zero, one real repeated solution; if negative, no real solutions. Understanding this helps identify equations with two real, distinct roots without solving.
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Square of a Binomial and Its Properties

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