Find a polynomial function ƒ(x) of least degree having only real coefficients and zeros as given. Assume multiplicity 1 unless otherwise stated. 2-i, 3, and -1
Ch. 3 - Polynomial and Rational Functions

Chapter 4, Problem 68
Solve each rational inequality. Give the solution set in interval notation.
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Start with the given inequality: \(\frac{5}{2 - x} > \frac{3}{3 - x}\).
Identify the domain restrictions by setting the denominators not equal to zero: \(2 - x \neq 0\) and \(3 - x \neq 0\), which means \(x \neq 2\) and \(x \neq 3\).
Bring all terms to one side to form a single rational expression: \(\frac{5}{2 - x} - \frac{3}{3 - x} > 0\).
Find a common denominator, which is \((2 - x)(3 - x)\), and combine the fractions: \(\frac{5(3 - x) - 3(2 - x)}{(2 - x)(3 - x)} > 0\).
Simplify the numerator and analyze the sign of the rational expression by considering the critical points from the numerator and denominator to determine the solution intervals.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Rational Inequalities
Rational inequalities involve expressions where variables appear in the denominator. Solving them requires finding values of the variable that make the inequality true, while ensuring the denominator is never zero to avoid undefined expressions.
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Nonlinear Inequalities
Finding a Common Denominator and Cross-Multiplication
To compare two rational expressions, you can cross-multiply when denominators are positive or find a common denominator to combine terms. Care must be taken to consider the sign of denominators, as multiplying or dividing by negative values reverses inequality signs.
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Finding Zeros & Their Multiplicity
Domain Restrictions and Interval Notation
The domain excludes values that make any denominator zero. After solving the inequality, solutions must be expressed in interval notation, clearly indicating which values satisfy the inequality and respecting domain restrictions.
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Interval Notation
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