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Ch. R - Review of Basic Concepts
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
Chapter 1, Problem 127

Simplify each expression. 1011(22z)\(\frac{10}{11}\) (22z)

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Identify the expression to simplify: \(\frac{10}{11} (22\theta)\).
Recognize that multiplication of a fraction by a term means multiplying the numerator by the term and keeping the denominator the same: \(\frac{10}{11} \times 22\theta = \frac{10 \times 22\theta}{11}\).
Multiply the constants in the numerator: \(10 \times 22 = 220\), so the expression becomes \(\frac{220\theta}{11}\).
Simplify the fraction by dividing the numerator and denominator by their greatest common divisor, which is 11: \(\frac{220\theta}{11} = \frac{220 \div 11 \times \theta}{11 \div 11} = 20\theta\).
Write the simplified expression as \(20\theta\).

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Key Concepts

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