Find an nth-degree polynomial function with real coefficients satisfying the given conditions. If you are using a graphing utility, use it to graph the function and verify the real zeros and the given function value. n=3; -5 and 4+3i are zeros; f(2) = 91

Verified step by step guidance

1. Identify the given zeros of the polynomial. Since the polynomial has real coefficients and one zero is complex (4 + 3i), its complex conjugate (4 - 3i) must also be a zero. So, the zeros are -5, 4 + 3i, and 4 - 3i.
2. Write the factors corresponding to each zero. For zero -5, the factor is \((x + 5)\). For zeros \$4 + 3i\( and \)4 - 3i\(, the factors are \)(x - (4 + 3i))\( and \)(x - (4 - 3i))$ respectively.
3. Multiply the complex conjugate factors to get a quadratic factor with real coefficients: \[(x - (4 + 3i))(x - (4 - 3i)) = (x - 4 - 3i)(x - 4 + 3i)\] Use the difference of squares formula to simplify this product.
4. Express the polynomial function as \(f(x) = a(x + 5)(x^2 - 8x + 25)\), where \(a\) is a real number constant to be determined.
5. Use the given function value \(f(2) = 91\) to find \(a\). Substitute \(x = 2\) into the polynomial and set the expression equal to 91, then solve for \(a\).

Key Concepts

Polynomial Zeros and Complex Conjugates

For polynomials with real coefficients, non-real zeros always come in conjugate pairs. Given a zero like 4 + 3i, its conjugate 4 - 3i must also be a zero. This ensures the polynomial remains with real coefficients when expanded.

Constructing a Polynomial from Zeros

A polynomial can be formed by multiplying factors corresponding to its zeros. For zeros r1, r2, and r3, the polynomial is f(x) = a(x - r1)(x - r2)(x - r3), where 'a' is a leading coefficient determined by additional conditions.

Using Function Values to Determine Leading Coefficient

Given a specific function value like f(2) = 91, substitute x = 2 into the polynomial expression and solve for the leading coefficient 'a'. This step ensures the polynomial satisfies all given conditions.