Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
2. Intro to Derivatives
Differentiability
Problem 3.68
Textbook Question
a. Graph the function
ƒ(x) = { x, -1 ≤ x < 0
{ tan x, 0 ≤ x ≤ π/4.
b. Is ƒ continuous at x = 0?
c. Is ƒ differentiable at x = 0?
Give reasons for your answers.

1
Step 1: To graph the function ƒ(x), first consider the piecewise definition. For the interval -1 ≤ x < 0, the function is ƒ(x) = x, which is a linear function. Plot this part of the graph as a straight line starting at x = -1 and ending just before x = 0.
Step 2: For the interval 0 ≤ x ≤ π/4, the function is ƒ(x) = tan(x). Plot this part of the graph starting at x = 0 and ending at x = π/4. Note that tan(x) is continuous and differentiable within this interval.
Step 3: To determine if ƒ is continuous at x = 0, check the left-hand limit and right-hand limit as x approaches 0. The left-hand limit is the value of ƒ(x) as x approaches 0 from the left, which is 0. The right-hand limit is the value of ƒ(x) as x approaches 0 from the right, which is tan(0) = 0. Since both limits are equal and ƒ(0) = tan(0) = 0, ƒ is continuous at x = 0.
Step 4: To determine if ƒ is differentiable at x = 0, check the derivative from the left and right. The derivative of ƒ(x) = x for x < 0 is 1, and the derivative of ƒ(x) = tan(x) for x > 0 is sec²(x). Evaluate sec²(x) at x = 0, which is 1. Since both derivatives are equal at x = 0, ƒ is differentiable at x = 0.
Step 5: Summarize the findings: The function ƒ(x) is continuous at x = 0 because the left-hand limit, right-hand limit, and ƒ(0) are all equal. It is differentiable at x = 0 because the derivatives from the left and right are equal at that point.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Piecewise Functions
A piecewise function is defined by different expressions based on the input value. In this case, the function ƒ(x) has two distinct parts: one for values of x from -1 to 0, and another for values from 0 to π/4. Understanding how to evaluate and graph each piece is crucial for analyzing the overall behavior of the function.
Recommended video:
Piecewise Functions
Continuity
A function is continuous at a point if the limit of the function as it approaches that point equals the function's value at that point. For ƒ(x) to be continuous at x = 0, we need to check if the left-hand limit (as x approaches 0 from the left) equals the right-hand limit (as x approaches 0 from the right) and if both equal ƒ(0).
Recommended video:
Intro to Continuity
Differentiability
A function is differentiable at a point if it has a defined derivative at that point, which requires the function to be continuous there. To determine if ƒ(x) is differentiable at x = 0, we must examine the left-hand and right-hand derivatives at that point and see if they are equal. If they differ, the function is not differentiable at that point.
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