Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
1. Limits and Continuity
Introduction to Limits
Problem 14d
Textbook Question
The position of an object moving vertically along a line is given by the function s(t)=−4.9t2+30t+20. Find the average velocity of the object over the following intervals.
[0,h], where h>0 is a real number
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1
Identify the formula for average velocity over an interval [a, b], which is given by the change in position divided by the change in time: \( v_{avg} = \frac{s(b) - s(a)}{b - a} \).
In this problem, the interval is [0, h], so we need to find the average velocity over this interval. Set \( a = 0 \) and \( b = h \).
Substitute the values into the average velocity formula: \( v_{avg} = \frac{s(h) - s(0)}{h - 0} \).
Calculate \( s(h) \) by substituting \( t = h \) into the position function: \( s(h) = -4.9h^2 + 30h + 20 \).
Calculate \( s(0) \) by substituting \( t = 0 \) into the position function: \( s(0) = -4.9(0)^2 + 30(0) + 20 = 20 \).
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