Let $f\left(x\right)=\frac{x^2-4}{x-2}$ . <IMAGE>
Calculate $f\left(x\right)$ for each value of $x$ in the following table.

Verified step by step guidance

1. First, let's simplify the function \( f(x) = \frac{x^2 - 4}{x - 2} \). Notice that the numerator \( x^2 - 4 \) can be factored as a difference of squares: \( (x - 2)(x + 2) \).
2. Rewrite the function using the factored form: \( f(x) = \frac{(x - 2)(x + 2)}{x - 2} \).
3. Observe that the \( x - 2 \) terms in the numerator and the denominator can be canceled out, but only for \( x \neq 2 \) to avoid division by zero. Thus, \( f(x) = x + 2 \) for \( x \neq 2 \).
4. Now, for each value of \( x \) in the table, substitute \( x \) into the simplified function \( f(x) = x + 2 \) to find the corresponding value of \( f(x) \).
5. Remember to handle the case where \( x = 2 \) separately, as the original function is undefined at this point due to division by zero. Consider the limit as \( x \) approaches 2 if needed.