Sag angle Imagine a climber clipping onto the rope described in Example 7 and pulling himself to the rope’s midpoint. Because the rope is supporting the weight of the climber, it no longer takes the shape of the catenary y = 200 cosh x/200. Instead, the rope (nearly) forms two sides of an isosceles triangle. Compute the sag angle θ illustrated in the figure, assuming the rope does not stretch when weighted. Recall from Example 7 that the length of the rope is 101 ft.
Table of contents
- 0. Functions7h 55m
- Introduction to Functions18m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms36m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 3h 16m
- 11. Integrals of Inverse, Exponential, & Logarithmic Functions2h 31m
- 12. Techniques of Integration7h 41m
- 13. Intro to Differential Equations2h 55m
- 14. Sequences & Series5h 36m
- 15. Power Series2h 19m
- 16. Parametric Equations & Polar Coordinates7h 58m
0. Functions
Trigonometric Identities
Multiple Choice
Simplify the expression.
(sin2θtan2θ−1)csc2(θ)cos2(−θ)
A
cot2θ
B
tanθ
C
1
D
– 1
1 Comment
Verified step by step guidance1
Start by rewriting the given expression: \( \left( \frac{\tan^2\theta}{\sin^2\theta} - 1 \right) \csc^2(\theta) \cos^2(-\theta) \).
Recall the trigonometric identities: \( \tan^2\theta = \frac{\sin^2\theta}{\cos^2\theta} \), \( \csc^2\theta = \frac{1}{\sin^2\theta} \), and \( \cos^2(-\theta) = \cos^2\theta \).
Substitute these identities into the expression: \( \left( \frac{\frac{\sin^2\theta}{\cos^2\theta}}{\sin^2\theta} - 1 \right) \frac{1}{\sin^2\theta} \cos^2\theta \).
Simplify the expression inside the parentheses: \( \frac{1}{\cos^2\theta} - 1 \).
Recognize that \( \frac{1}{\cos^2\theta} - 1 = \tan^2\theta \), and simplify the entire expression to find the result.
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