Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
6. Derivatives of Inverse, Exponential, & Logarithmic Functions
Derivatives of Inverse Trigonometric Functions
Problem 3.10.5
Textbook Question
Suppose f is a one-to-one function with f(2)=8 and f′(2)=4. What is the value of (f^−1)′(8)?

1
Step 1: Recall the formula for the derivative of the inverse function. If f is a one-to-one function and differentiable at a point, then the derivative of its inverse function at a point is given by: \((f^{-1})'(b) = \frac{1}{f'(a)}\), where \(f(a) = b\).
Step 2: Identify the given values in the problem. We know that \(f(2) = 8\) and \(f'(2) = 4\).
Step 3: Match the given values to the formula. Here, \(a = 2\) and \(b = 8\), so we need to find \((f^{-1})'(8)\).
Step 4: Substitute the known values into the formula. Using \((f^{-1})'(b) = \frac{1}{f'(a)}\), substitute \(f'(2) = 4\) into the formula to find \((f^{-1})'(8)\).
Step 5: Calculate the expression \((f^{-1})'(8) = \frac{1}{4}\). This gives the value of the derivative of the inverse function at the point where \(f(x) = 8\).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Inverse Function Theorem
The Inverse Function Theorem states that if a function f is continuously differentiable and has a non-zero derivative at a point, then its inverse function f⁻¹ is also differentiable at the corresponding point. Specifically, if f'(a) ≠ 0, then (f⁻¹)'(f(a)) = 1 / f'(a). This theorem is crucial for finding the derivative of an inverse function.
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One-to-One Function
A one-to-one function, or injective function, is a function where each output is produced by exactly one input. This property ensures that the function has an inverse, as it guarantees that for every y in the range, there is a unique x in the domain such that f(x) = y. In this problem, knowing that f is one-to-one allows us to confidently apply the Inverse Function Theorem.
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Derivative of a Function
The derivative of a function at a point measures the rate at which the function's value changes as its input changes. It is defined as the limit of the average rate of change as the interval approaches zero. In this context, f′(2) = 4 indicates that at x = 2, the function f is increasing at a rate of 4 units of output for every 1 unit of input, which is essential for calculating the derivative of the inverse function.
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