Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
5. Graphical Applications of Derivatives
Applied Optimization
Problem 4.5.71b
Textbook Question
Cylinder in a cone A right circular cylinder is placed inside a cone of radius R and height H so that the base of the cylinder lies on the base of the cone.
b. Find the dimensions of the cylinder with maximum lateral surface area (area of the curved surface).

1
Understand the problem: We need to find the dimensions of a cylinder with maximum lateral surface area that fits inside a cone with given radius R and height H. The lateral surface area of a cylinder is given by the formula: \( A = 2\pi rh \), where \( r \) is the radius and \( h \) is the height of the cylinder.
Set up the relationship between the cone and the cylinder: The cylinder is inscribed in the cone, so its dimensions are constrained by the cone's dimensions. The cone's equation in terms of its height and radius is \( \frac{r}{R} = \frac{H-h}{H} \), where \( r \) and \( h \) are the radius and height of the cylinder, respectively.
Express the height of the cylinder in terms of its radius: From the relationship \( \frac{r}{R} = \frac{H-h}{H} \), solve for \( h \) to get \( h = H - \frac{Hr}{R} \).
Substitute \( h \) in the lateral surface area formula: Replace \( h \) in \( A = 2\pi rh \) with the expression from the previous step to get \( A = 2\pi r(H - \frac{Hr}{R}) \). Simplify this to \( A = 2\pi rH - \frac{2\pi Hr^2}{R} \).
Find the maximum lateral surface area: To maximize \( A \), take the derivative of \( A \) with respect to \( r \), set it to zero, and solve for \( r \). This will give the radius of the cylinder that maximizes the lateral surface area. Use this \( r \) to find the corresponding \( h \) using the expression from step 3.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Lateral Surface Area of a Cylinder
The lateral surface area of a cylinder is the area of the curved surface that connects the top and bottom bases. It can be calculated using the formula A = 2πrh, where r is the radius of the base and h is the height of the cylinder. Understanding this concept is crucial for determining how to maximize the surface area in the context of the problem.
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Optimization in Calculus
Optimization involves finding the maximum or minimum values of a function within a given domain. In this problem, we need to apply techniques such as taking derivatives and setting them to zero to find the dimensions of the cylinder that maximize its lateral surface area. This concept is fundamental in calculus for solving real-world problems involving constraints.
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Geometric Relationships in 3D Shapes
Understanding the geometric relationships between the cylinder and the cone is essential for this problem. The dimensions of the cylinder are constrained by the dimensions of the cone, specifically its radius R and height H. This relationship can be expressed using similar triangles, which helps in deriving the equations needed to optimize the lateral surface area.
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