- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals3h 25m
0. Functions
Introduction to Functions
Problem 2
Textbook Question
Express the radius of a sphere as a function of the sphere’s surface area. Then express the surface area as a function of the volume.

1
Start by recalling the formula for the surface area of a sphere, which is given by \( S = 4\pi r^2 \), where \( S \) is the surface area and \( r \) is the radius.
To express the radius \( r \) as a function of the surface area \( S \), solve the surface area formula for \( r \). Begin by dividing both sides by \( 4\pi \) to isolate \( r^2 \): \( r^2 = \frac{S}{4\pi} \).
Take the square root of both sides to solve for \( r \): \( r = \sqrt{\frac{S}{4\pi}} \). This expresses the radius as a function of the surface area.
Next, recall the formula for the volume of a sphere, which is \( V = \frac{4}{3}\pi r^3 \), where \( V \) is the volume.
To express the surface area \( S \) as a function of the volume \( V \), first solve the volume formula for \( r \): \( r = \left(\frac{3V}{4\pi}\right)^{1/3} \). Substitute this expression for \( r \) into the surface area formula \( S = 4\pi r^2 \) to express \( S \) in terms of \( V \).
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