Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Related Rates
Problem 3.1.48
Textbook Question
Interpreting the derivative Find the derivative of each function at the given point and interpret the physical meaning of this quantity. Include units in your answer.
When a faucet is turned on to fill a bathtub, the volume of water in gallons in the tub after t minutes is V(t)=3t. Find V′(12).

1
First, identify the function given: V(t) = 3t, which represents the volume of water in the bathtub in gallons as a function of time in minutes.
To find the derivative V'(t), apply the basic rule of differentiation for a linear function. The derivative of V(t) = 3t with respect to t is V'(t) = 3.
Evaluate the derivative at the given point t = 12. Since V'(t) = 3, V'(12) = 3.
Interpret the physical meaning of the derivative V'(12) = 3. This means that the rate at which the volume of water in the bathtub is increasing is 3 gallons per minute.
Include units in your interpretation: The derivative V'(12) = 3 gallons per minute indicates that at t = 12 minutes, the water is being added to the bathtub at a constant rate of 3 gallons per minute.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Derivative
The derivative of a function measures the rate at which the function's value changes with respect to changes in its input. In this context, it represents the instantaneous rate of change of the volume of water in the bathtub with respect to time. Mathematically, it is defined as the limit of the average rate of change as the interval approaches zero.
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Physical Interpretation of Derivatives
In applied contexts, the derivative can be interpreted as a physical quantity. For the function V(t) = 3t, the derivative V′(t) indicates how quickly the volume of water is increasing at a specific time. This can be understood as the flow rate of water into the bathtub, typically measured in gallons per minute.
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Units of Measurement
When calculating derivatives in real-world scenarios, it is essential to include appropriate units to convey the meaning of the result. In this case, since V(t) is measured in gallons and t in minutes, the derivative V′(t) will have units of gallons per minute, providing a clear understanding of the rate at which water is being added to the bathtub.
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