Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
2. Intro to Derivatives
Derivatives as Functions
Problem 3.6.9
Textbook Question
The speed of sound (in m/s) in dry air is approximated the function v(T) = 331 + 0.6T, where T is the air temperature (in degrees Celsius). Evaluate v' (T) and interpret its meaning.

1
Step 1: Identify the given function v(T) = 331 + 0.6T, which represents the speed of sound in dry air as a function of temperature T.
Step 2: Recognize that v'(T) represents the derivative of the function v(T) with respect to T, which gives the rate of change of the speed of sound with respect to temperature.
Step 3: Differentiate the function v(T) = 331 + 0.6T with respect to T. Since 331 is a constant, its derivative is 0. The derivative of 0.6T with respect to T is 0.6.
Step 4: Conclude that v'(T) = 0.6. This means that for each degree Celsius increase in temperature, the speed of sound increases by 0.6 meters per second.
Step 5: Interpret the result: The derivative v'(T) = 0.6 indicates that the speed of sound in dry air increases linearly with temperature at a constant rate of 0.6 m/s per degree Celsius.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Derivative
The derivative of a function measures the rate at which the function's value changes as its input changes. In this context, v'(T) represents the rate of change of the speed of sound with respect to temperature. It provides insight into how sensitive the speed of sound is to variations in temperature.
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Function Interpretation
Understanding the function v(T) = 331 + 0.6T involves recognizing that it is a linear function where the speed of sound increases with temperature. The constant 331 m/s represents the speed of sound at 0 degrees Celsius, while the coefficient 0.6 indicates the increase in speed for each degree rise in temperature.
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Physical Context of Derivatives
In physics, derivatives often have practical interpretations. For this problem, v'(T) not only quantifies how the speed of sound changes with temperature but also reflects the physical phenomenon that sound travels faster in warmer air. This relationship is crucial for applications in meteorology and acoustics.
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