Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Motion Analysis
Problem 3.6.11c
Textbook Question
Highway travel A state patrol station is located on a straight north-south freeway. A patrol car leaves the station at 9:00 A.M. heading north with position function s = f(t) that gives its location in miles t hours after 9:00 A.M. (see figure). Assume s is positive when the car is north of the patrol station. <IMAGE>
c. Find the average velocity of the car over the interval [1.75, 2.25]. Estimate the velocity of the car at 11:00 A.M. and determine the direction in which the patrol car is moving.

1
To find the average velocity of the car over the interval [1.75, 2.25], use the formula for average velocity: \( v_{avg} = \frac{f(b) - f(a)}{b - a} \), where \( a = 1.75 \) and \( b = 2.25 \).
Substitute the values of \( a \) and \( b \) into the formula: \( v_{avg} = \frac{f(2.25) - f(1.75)}{2.25 - 1.75} \).
To estimate the velocity of the car at 11:00 A.M., which corresponds to \( t = 2 \) hours after 9:00 A.M., find the derivative of the position function \( s = f(t) \) to get the velocity function \( v(t) = f'(t) \).
Evaluate the derivative at \( t = 2 \) to estimate the velocity: \( v(2) = f'(2) \).
Determine the direction of the patrol car by checking the sign of \( v(2) \). If \( v(2) > 0 \), the car is moving north; if \( v(2) < 0 \), the car is moving south.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Average Velocity
Average velocity is defined as the change in position divided by the time interval over which that change occurs. Mathematically, it is calculated as (s(t2) - s(t1)) / (t2 - t1), where s(t) is the position function. In this context, it helps determine how fast the patrol car is moving on average between two specific times.
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Position Function
The position function s = f(t) describes the location of an object at any given time t. In this scenario, it represents the distance of the patrol car from the station in miles, where t is measured in hours after 9:00 A.M. Understanding this function is crucial for calculating both average and instantaneous velocities.
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Instantaneous Velocity
Instantaneous velocity refers to the velocity of an object at a specific moment in time, which can be found by taking the derivative of the position function with respect to time. This concept is essential for estimating the patrol car's speed at 11:00 A.M. and determining its direction of movement, as it indicates whether the car is moving north or south.
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