Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
2. Intro to Derivatives
Tangent Lines and Derivatives
Problem 37b
Textbook Question
Derivatives and tangent lines
b. Determine an equation of the line tangent to the graph of f at the point (a,f(a)) for the given value of a.
f(x) = 1/ √x; a= 1/4

1
Step 1: Find the derivative of the function f(x) = \frac{1}{\sqrt{x}}. Rewrite the function as f(x) = x^{-1/2} to make differentiation easier.
Step 2: Use the power rule for differentiation, which states that \frac{d}{dx}[x^n] = nx^{n-1}, to find f'(x). For f(x) = x^{-1/2}, the derivative f'(x) = -\frac{1}{2}x^{-3/2}.
Step 3: Evaluate the derivative at the given point a = \frac{1}{4}. Substitute x = \frac{1}{4} into f'(x) to find the slope of the tangent line at this point.
Step 4: Calculate f(a) by substituting a = \frac{1}{4} into the original function f(x) = \frac{1}{\sqrt{x}}. This will give you the y-coordinate of the point of tangency.
Step 5: Use the point-slope form of a line, y - y_1 = m(x - x_1), where m is the slope found in Step 3 and (x_1, y_1) is the point (\frac{1}{4}, f(\frac{1}{4})), to write the equation of the tangent line.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Derivatives
A derivative represents the rate of change of a function with respect to its variable. It is defined as the limit of the average rate of change of the function as the interval approaches zero. In practical terms, the derivative at a point gives the slope of the tangent line to the graph of the function at that point.
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Tangent Line
A tangent line to a curve at a given point is a straight line that touches the curve at that point without crossing it. The slope of the tangent line is equal to the derivative of the function at that point. The equation of the tangent line can be expressed using the point-slope form, which incorporates the slope and the coordinates of the point of tangency.
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Point-Slope Form
The point-slope form of a linear equation is given by y - y₁ = m(x - x₁), where (x₁, y₁) is a point on the line and m is the slope. This form is particularly useful for writing the equation of a tangent line once the slope (derivative) and the point of tangency are known. It allows for a straightforward way to express the line based on its slope and a specific point.
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