Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Related Rates
Problem 12a
Textbook Question
Shrinking square The sides of a square decrease in length at a rate of 1 m/s.
a. At what rate is the area of the square changing when the sides are 5 m long?

1
Identify the relationship between the side length of the square and its area. The area \( A \) of a square with side length \( s \) is given by \( A = s^2 \).
Recognize that the problem involves rates of change, which suggests using derivatives. We need to find \( \frac{dA}{dt} \), the rate of change of the area with respect to time.
Apply the chain rule to differentiate the area with respect to time: \( \frac{dA}{dt} = \frac{d}{dt}(s^2) = 2s \frac{ds}{dt} \).
Substitute the given values into the differentiated equation. We know \( \frac{ds}{dt} = -1 \) m/s (since the side is decreasing) and \( s = 5 \) m.
Calculate \( \frac{dA}{dt} \) using the substituted values: \( \frac{dA}{dt} = 2 \times 5 \times (-1) \). This will give the rate at which the area is changing when the sides are 5 m long.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Related Rates
Related rates involve finding the rate at which one quantity changes in relation to another. In this problem, we need to determine how the area of the square changes as the length of its sides decreases. This requires applying the chain rule from calculus to relate the rates of change of the side length and the area.
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Area of a Square
The area of a square is calculated using the formula A = s², where s is the length of a side. As the side length changes, the area will also change. Understanding this relationship is crucial for determining how the area is affected by the rate at which the side length is decreasing.
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Chain Rule
The chain rule is a fundamental principle in calculus used to differentiate composite functions. In this context, it allows us to express the rate of change of the area with respect to time by relating it to the rate of change of the side length. This is essential for solving the problem and finding the rate at which the area is changing.
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