Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
3. Techniques of Differentiation
Product and Quotient Rules
Problem 57
Textbook Question
Find and simplify the derivative of the following functions.
h(x) = (5x7 + 5x)(6x3 + 3x2 + 3)
![](/channels/images/assetPage/verifiedSolution.png)
1
Step 1: Identify the function h(x) = (5x^7 + 5x)(6x^3 + 3x^2 + 3) as a product of two functions, u(x) = 5x^7 + 5x and v(x) = 6x^3 + 3x^2 + 3.
Step 2: Apply the product rule for derivatives, which states that if h(x) = u(x)v(x), then h'(x) = u'(x)v(x) + u(x)v'(x).
Step 3: Differentiate u(x) = 5x^7 + 5x to find u'(x). Use the power rule: d/dx[x^n] = nx^(n-1).
Step 4: Differentiate v(x) = 6x^3 + 3x^2 + 3 to find v'(x). Again, use the power rule for each term.
Step 5: Substitute u(x), u'(x), v(x), and v'(x) into the product rule formula to find h'(x) and simplify the expression.
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