Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
1. Limits and Continuity
Introduction to Limits
Problem 5cb
Textbook Question
The table gives the position s(t)of an object moving along a line at time t, over a two-second interval. Find the average velocity of the object over the following intervals. <IMAGE>
c. [0,1]
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1
Identify the formula for average velocity over an interval [a, b], which is given by the change in position divided by the change in time: \( v_{avg} = \frac{s(b) - s(a)}{b - a} \).
Determine the values of \( s(0) \) and \( s(1) \) from the table provided. These represent the position of the object at time \( t = 0 \) and \( t = 1 \) respectively.
Substitute the values of \( s(0) \) and \( s(1) \) into the average velocity formula: \( v_{avg} = \frac{s(1) - s(0)}{1 - 0} \).
Simplify the expression by calculating the difference \( s(1) - s(0) \) to find the change in position.
Divide the change in position by the change in time (which is 1 second in this case) to find the average velocity over the interval [0, 1].
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