Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
4. Applications of Derivatives
Implicit Differentiation
Problem 3.8.80b
Textbook Question
79–82. {Use of Tech} Visualizing tangent and normal lines
b. Graph the tangent and normal lines on the given graph.
x⁴ = 2x²+2y²; (x0, y0)=(2, 2) (kampyle of Eudoxus)

1
First, understand the problem: We need to find the equations of the tangent and normal lines to the curve given by \(x^4 = 2x^2 + 2y^2\) at the point \((x_0, y_0) = (2, 2)\).
To find the tangent line, we need the derivative of the curve. Start by implicitly differentiating the equation \(x^4 = 2x^2 + 2y^2\) with respect to \(x\). Use the chain rule for \(y^2\) since \(y\) is a function of \(x\).
After differentiating, solve for \(\frac{dy}{dx}\), which represents the slope of the tangent line at any point \((x, y)\) on the curve.
Substitute \((x_0, y_0) = (2, 2)\) into the derivative to find the slope of the tangent line at this specific point.
Use the point-slope form of a line, \(y - y_0 = m(x - x_0)\), where \(m\) is the slope found in the previous step, to write the equation of the tangent line. The normal line is perpendicular to the tangent line, so its slope is the negative reciprocal of the tangent line's slope. Use this to write the equation of the normal line.

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Tangent Line
A tangent line to a curve at a given point is a straight line that touches the curve at that point without crossing it. It represents the instantaneous rate of change of the function at that point, which can be found using the derivative. For the curve defined by the equation, the slope of the tangent line can be calculated by differentiating the equation implicitly.
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Normal Line
The normal line at a point on a curve is perpendicular to the tangent line at that point. Its slope is the negative reciprocal of the slope of the tangent line. Understanding the normal line is essential for visualizing how the curve behaves at that point, and it can also be derived from the tangent line's slope.
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Slopes of Tangent Lines
Implicit Differentiation
Implicit differentiation is a technique used to differentiate equations where the dependent and independent variables are not isolated. In this case, the equation x⁴ = 2x² + 2y² involves both x and y. By differentiating both sides with respect to x, we can find dy/dx, which is necessary to determine the slopes of the tangent and normal lines.
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