Table of contents
- 0. Functions7h 52m
- Introduction to Functions16m
- Piecewise Functions10m
- Properties of Functions9m
- Common Functions1h 8m
- Transformations5m
- Combining Functions27m
- Exponent rules32m
- Exponential Functions28m
- Logarithmic Functions24m
- Properties of Logarithms34m
- Exponential & Logarithmic Equations35m
- Introduction to Trigonometric Functions38m
- Graphs of Trigonometric Functions44m
- Trigonometric Identities47m
- Inverse Trigonometric Functions48m
- 1. Limits and Continuity2h 2m
- 2. Intro to Derivatives1h 33m
- 3. Techniques of Differentiation3h 18m
- 4. Applications of Derivatives2h 38m
- 5. Graphical Applications of Derivatives6h 2m
- 6. Derivatives of Inverse, Exponential, & Logarithmic Functions2h 37m
- 7. Antiderivatives & Indefinite Integrals1h 26m
- 8. Definite Integrals4h 44m
- 9. Graphical Applications of Integrals2h 27m
- 10. Physics Applications of Integrals 2h 22m
2. Intro to Derivatives
Derivatives as Functions
Problem 3.1.59
Textbook Question
Find the function The following limits represent the slope of a curve y = f(x) at the point (a,f(a)). Determine a possible function f and number a; then calculate the limit.
(lim h🠂0) (2+h)⁴-16 / h

1
Step 1: Recognize that the given limit expression represents the derivative of a function at a point. The expression \( \lim_{h \to 0} \frac{(2+h)^4 - 16}{h} \) is in the form of the difference quotient \( \frac{f(a+h) - f(a)}{h} \), which is used to find the derivative of a function \( f(x) \) at \( x = a \).
Step 2: Identify the function \( f(x) \) and the point \( a \). Notice that \( (2+h)^4 \) suggests that \( f(x) = x^4 \) and \( a = 2 \) because \( f(2) = 2^4 = 16 \).
Step 3: Confirm that the expression matches the derivative form. Substitute \( f(x) = x^4 \) and \( a = 2 \) into the difference quotient: \( \frac{(2+h)^4 - 2^4}{h} \). This matches the given limit expression.
Step 4: Expand \( (2+h)^4 \) using the binomial theorem or direct expansion: \( (2+h)^4 = 16 + 32h + 24h^2 + 8h^3 + h^4 \).
Step 5: Substitute the expanded form back into the limit expression: \( \lim_{h \to 0} \frac{32h + 24h^2 + 8h^3 + h^4}{h} \). Simplify by canceling \( h \) from the numerator and denominator, then evaluate the limit as \( h \to 0 \).

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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Limits
Limits are fundamental in calculus, representing the value that a function approaches as the input approaches a certain point. In this context, the limit is used to find the slope of the curve at a specific point, which is essential for understanding the behavior of the function near that point.
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Derivative
The derivative of a function at a point quantifies the rate of change of the function with respect to its variable. It is defined as the limit of the average rate of change as the interval approaches zero. In this problem, calculating the limit will yield the derivative of the function at the point (a, f(a)).
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Function Evaluation
Function evaluation involves substituting a specific value into a function to determine its output. In this case, identifying a function f and a number a is crucial for calculating the limit and finding the slope of the curve at the point of interest, which is a key step in solving the problem.
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