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Ch. 5 - The Structure and Function of Large Biological Molecules
Chapter 5, Problem 7

Which of the following pairs of base sequences could form a short stretch of a normal double helix of DNA? a. 5′-AGCT-3′ with 5′-TCGA-3′ b. 5′-GCGC-3′ with 5′-TATA-3′ c. 5′-ATGC-3′ with 5′-GCAT-3′ d. All of these pairs are correct.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Base Pairing Rules

Base pairing rules dictate how nucleotides in DNA pair with each other. Adenine (A) pairs with Thymine (T), and Cytosine (C) pairs with Guanine (G). This complementary pairing is essential for the formation of the double helix structure of DNA, ensuring accurate replication and transcription.
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DNA Structure

DNA is structured as a double helix, consisting of two strands that run in opposite directions (antiparallel). Each strand is composed of a sugar-phosphate backbone and nitrogenous bases. The specific orientation of the strands (5' to 3' direction) is crucial for understanding how base pairs align and interact.
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Nucleotide Sequences

Nucleotide sequences refer to the order of nitrogenous bases in a DNA strand. The sequence determines the genetic information carried by the DNA. When evaluating pairs of sequences for compatibility in forming a double helix, it is important to consider both the base pairing and the orientation of the strands.
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Related Practice
Textbook Question

The structural level of a protein least affected by a disruption in hydrogen bonding is the a. primary level. b. secondary level. c. tertiary level. d. quaternary level.

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Textbook Question

Enzymes that break down DNA catalyze the hydrolysis of the covalent bonds that join nucleotides together. What would happen to DNA molecules treated with these enzymes? a. The two strands of the double helix would separate. b. The phosphodiester linkages of the polynucleotide backbone would be broken. c. The pyrimidines would be separated from the deoxyribose sugars. d. All bases would be separated from the deoxyribose sugars.

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Textbook Question

The molecular formula for glucose is C6H12O6. What would be the molecular formula for a polymer made by linking ten glucose molecules together by dehydration reactions? a. C60H120O60 b. C60H102O51 c. C60H100O50 d. C60H111O51

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Textbook Question

Construct a table that organizes the following terms, and label the columns and rows.

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Textbook Question

DRAW IT Copy the polynucleotide strand in Figure 5.23a and label the bases G, T, C, and T, starting from the 5′ end. Assuming this is a DNA polynucleotide, now draw the complementary strand, using the same symbols for phosphates (circles), sugars (pentagons), and bases. Label the bases. Draw arrows showing the 5'→3' direction of each strand. Use the arrows to make sure the second strand is antiparallel to the first. Hint: After you draw the first strand vertically, turn the paper upside down; it is easier to draw the second strand from the 5′ toward the 3′ direction as you go from top to bottom.

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