After telophase I of meiosis, each daughter cell is                   . a. diploid, and the chromosomes are composed of one double-stranded DNA molecule; b. diploid, and the chromosomes are composed of two sister chromatids; c. haploid, and the chromosomes are composed of one double-stranded DNA molecule; d. haploid, and the chromosomes are composed of two sister chromatids

Video transcript

Welcome back. Here's our next problem. After a human cell undergoes Tell a phase one of my aosis a blank develops dividing the cell into two blank daughter cells with chromosomes consisting of two sister chroma tits. So we need to fill in two blanks here. Let's start with the first one. And we're talking about what happens after undergoing Tell a phase one. So what is the structure that develops that divides the cell into its daughter cells? When we look at our answer choices, we have two choices here. Uh Two of the answers have cell plate and to have cleavage furrow. Well cleavage furrow and we can be helped by the word cleavage. Think of cleaving something is indeed that structure that develops divide the cell so we can eliminate choices A. And D. Which have cell plate. A cell plate actually is part of that dividing of cells in plant cells. Um It was the precursor the cell wall that will develop between both. But we know from our problem that we have a human cell so it won't have a cell plate. The cleavage furrow is what will develop. So let's go into part two when we look at B&C. Are choices either Hap Lloyd or deployed daughter cells. Well let's remember that in mitosis that we start with a half a deployed parent, deployed parent and we have deployed daughter cells. But in my Aosis we start with a deployed parent but end up with hap Lloyd daughter selves. However, we know that may tome aosis has two rounds of cell cell division mitosis one and may aosis too. So we need to remind ourselves of what state those daughter cells are in Um after the after round one. Are they happily or deployed? Well this one we start with that deployed parent. So we have two of every chromosome in that round of cell division the homologous pairs Like this one separate. And so we end up with hap Lloyd daughter selves, two of them, each one with one of that set of chromosomes. And but those chromosomes do have to sister chroma tits as our problem tells us. So just to remind ourselves, may Asus to these happily a daughter cells go into cell division the sister chroma tides separate. So you end up with four halfway daughter cells. That happened in both cases. But these guys only have a single chromatic so both rounds result in halfway daughter cells. It just they differentiate by how many of the sister chroma tides they have. So let's look back at our answer choices and we'll want to choose B happy Lloyd daughter cells and eliminate C. Where the choice is deployed. So our answer is B After a human cell undergoes tell a phase one of my Asus A cleavage furrow develops dividing the cell into two half Lloyd daughter cells with chromosomes consisting of two sister chroma tits. See you in the next video