Based on the previous example calculate the molarity value for each student if they dissolve 0.300 (± 0.03) moles of analyte. 

• A. 1.5 ± 0.2 M for both
• B. 1.5 ± 0.2 M for student A and 1.5 ± 0.1 M for student B
• C. 1.5 ± 0.1 M for student A and 1.5 ± 0.2 M for student B
• D. 1.5 ± 0.04 M for student A and 1.5 ± 0.01 M for student B

Answer: (A)

Verified step by step guidance

1. Identify the formula for molarity, which is M = \(\frac{n}{V}\), where M is the molarity, n is the number of moles, and V is the volume in liters.
2. Determine the number of moles of the analyte, which is given as 0.300 moles with an uncertainty of ± 0.03 moles.
3. Assume a volume for the solution based on the context or previous example, as it is not provided in the problem. This volume should be in liters.
4. Calculate the molarity by dividing the number of moles by the volume in liters. Consider the uncertainty in the number of moles when calculating the uncertainty in molarity.
5. Compare the calculated molarity and its uncertainty with the given options to determine which matches the calculated values for each student.