Trigonometry
Write the point that lies on the graph of y=sin−1xy=\sin^{-1}xy=sin−1x if the point (π6,12)\left(\frac{\pi}{6},\frac12\right)(6π,21) lies on the graph of y=sinxy=\sin xy=sinx .
(12,π6)\left(\frac12,\frac{\pi}{6}\right)(21,6π)
(−12,−π6)\left(-\frac12,-\frac{\pi}{6}\right)(−21,−6π)
(12,π3)\left(\frac12,\frac{\pi}{3}\right)(21,3π)
(π6,−12)\left(\frac{\pi}{6},-\frac12\right)(6π,−21)