Trigonometry
Find the exact solution of the equation.
sin−1x+csc−11x=π3\sin^{-1}x+\csc^{-1}\frac{1}{x}=\frac{\pi}{3}sin−1x+csc−1x1=3π
{0}\left\lbrace0\right\rbrace{0}
{12}\left\lbrace\frac12\right\rbrace{21}
{−12}\left\lbrace-\frac12\right\rbrace{−21}
{0,12}\left\lbrace0,\frac12\right\rbrace{0,21}