Trigonometry
Determine the amplitude, period, phase shift, and vertical translation of the given trigonometric function.
y=9−sin(8x−π3)y=9-\sin\left(8x-\frac{\pi}{3}\right)
Amplitude = 1, period = π4\frac{\pi}{4}4π, phase shift: π24\frac{\pi}{24}24π unit to the left, vertical translation: 9 units up
Amplitude = 1, period = π4\frac{\pi}{4}4π, phase shift: π24\frac{\pi}{24}24π unit to the right, vertical translation: 9 units up
Amplitude = 9, period = π8\frac{\pi}{8}8π, phase shift: π24\frac{\pi}{24}24π unit to the left, vertical translation: 9 units down
Amplitude = 9, period = π8\frac{\pi}{8}8π, phase shift: π24\frac{\pi}{24}24π unit to the right, vertical translation: 1 unit down