Trigonometry
Write the following trigonometric expression in terms of sine and cosine. Express your answer in terms of xx only.
−csc2(−x)−cos2(x)−sin2(−x)-\csc^2\left(-x\right)-\cos^2\left(x\right)-\sin^2\left(-x\right)
(−1−sin2x)sin2x\frac{\left(-1-\sin^2x\right)}{\sin^2x}
(1−sin2x)sin2x\frac{\left(1-\sin^2x\right)}{\sin^2x}
(−1−sin2x)cos2x\frac{\left(-1-\sin^2x\right)}{\cos^2x}
(−1−sin2x)sinx\frac{\left(-1-\sin^2x\right)}{\sin x}