Trigonometry
Solve the following equation for x if x lies in the interval [−π2,π2]\left[-\frac{\pi}{2},\right.\left.\frac{\pi}{2}\right\rbrack[−2π,2π].
y=sinx−7y=\sin x-7y=sinx−7
x=sin−1(y−7)x=\sin^{-1}\left(y-7\right)x=sin−1(y−7)
x=sin−1(y+7)x=\sin^{-1}\left(y+7\right)x=sin−1(y+7)
x=sin−1(7y)x=\sin^{-1}\left(7y\right)x=sin−1(7y)
x=sin−1(y7)x=\sin^{-1}\left(\frac{y}{7}\right)x=sin−1(7y)