Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles39m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
8. Vectors
Geometric Vectors
Problem 7.42
Textbook Question
Textbook QuestionA force of 30.0 lb is required to hold an 80.0-lb pressure washer on an incline. What angle does the incline make with the horizontal?
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Forces on an Incline
When an object is on an incline, the forces acting on it can be resolved into components parallel and perpendicular to the surface. The weight of the object can be split into these components, where the parallel component causes the object to slide down the incline, and the perpendicular component is countered by the normal force.
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Example 2
Trigonometric Functions
Trigonometric functions, particularly sine and cosine, are essential for relating angles to the ratios of the sides of a right triangle. In the context of an incline, the sine of the angle can be used to find the ratio of the opposite side (force parallel to the incline) to the hypotenuse (weight of the object), while the cosine relates to the adjacent side (normal force).
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Equilibrium of Forces
In this scenario, the pressure washer is in equilibrium, meaning the forces acting on it are balanced. The force required to hold the washer in place (30.0 lb) equals the component of the weight acting down the incline. By applying the equilibrium condition, one can set up an equation to solve for the angle of the incline using the known forces.
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