Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles39m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
8. Vectors
Geometric Vectors
2:26 minutes
Problem 51
Textbook Question
Textbook QuestionIn Exercises 47–52, write the vector v in terms of i and j whose magnitude ||v|| and direction angle θ are given. ||v|| = 1/2, θ = 113°
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Magnitude of a Vector
The magnitude of a vector represents its length or size, denoted as ||v||. In this case, the magnitude is given as 1/2, indicating that the vector's length is half a unit. Understanding magnitude is essential for determining how far the vector extends in space.
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Direction Angle
The direction angle θ of a vector indicates the angle it makes with the positive x-axis, measured in degrees or radians. Here, θ is 113°, which means the vector is oriented 113° counterclockwise from the positive x-axis. This angle is crucial for calculating the vector's components along the x and y axes.
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Vector Components
Vector components are the projections of a vector along the coordinate axes, typically represented as i (x-component) and j (y-component). To express the vector v in terms of i and j, we use the formulas v = ||v|| * cos(θ) * i + ||v|| * sin(θ) * j. This allows us to break down the vector into its horizontal and vertical parts based on its magnitude and direction angle.
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