Find the area of each triangle ABC.
A = 42.5°, b = 13.6 ...

Question

Find the area of each triangle ABC.

A = 42.5°, b = 13.6 m, c = 10.1 m

Accepted Answer

Hello, today we are going to determine the area of a triangle. ABC. With the following measurements, we are told that angle A is equal to 48.5 degrees. Side length B is equal to 17.8 m and side length C is equal to 29.3 m. Now, there is a special form of the area of a triangle which states that if you are given two side links and an angle, you can multiply a half with the two side links and multiply sine of the given angle. Since we are given the angle A and Silins B and C. The equation of the area of the triangle we will be using is the area is equal to one half multiplied by sin length B multiplied by S length C multiplied by sine of angle A let's go ahead and plug in the given information to solve for the area. This is going to be one half multiplied by S length B which is 17.8 m multiplied by sil length C which is 29.3 m multiplied by sine of the angle A which is 48.5 degrees, multiplying a half with 17.8 and 29.3 will leave us with 260.77 m squared multiplied by sign of 48.5 degrees. At this point, I would recommend the help of a calculator and multiplying both of these values together will give us a final area of 195.3 m squared. This is going to be the area of a triangle with two given side links and one given angle. And with that being said, the answer to this problem is going to be D so I hope this video helps you in understanding how to approach this problem. And I'll go ahead and see you all in the next video.

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Find the area of each triangle ABC.
A = 42.5°, b = 13.6 m, c = 10.1 m