Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles39m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
11. Graphing Complex Numbers
Powers of Complex Numbers (DeMoivre's Theorem)
8:37 minutes
Problem 65
Textbook Question
Textbook QuestionIn Exercises 65–68, find all the complex roots. Write roots in polar form with θ in degrees. The complex square roots of 9(cos 30° + i sin 30°)
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Complex Numbers
Complex numbers are numbers that have a real part and an imaginary part, expressed in the form a + bi, where 'a' is the real part and 'b' is the imaginary part. In trigonometry, complex numbers can also be represented in polar form as r(cos θ + i sin θ), where 'r' is the magnitude and 'θ' is the angle. Understanding this representation is crucial for finding roots of complex numbers.
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Polar Form of Complex Numbers
The polar form of a complex number expresses it in terms of its magnitude and angle, using the formula r(cos θ + i sin θ). The magnitude 'r' is calculated as the square root of the sum of the squares of the real and imaginary parts, while 'θ' is the angle formed with the positive real axis. This form is particularly useful for operations like multiplication, division, and finding roots of complex numbers.
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Complex Numbers In Polar Form
Finding Roots of Complex Numbers
To find the roots of a complex number in polar form, we use De Moivre's Theorem, which states that for a complex number r(cos θ + i sin θ), the nth roots can be found using the formula r^(1/n)(cos(θ/n + k(360°/n)) + i sin(θ/n + k(360°/n))) for k = 0, 1, ..., n-1. This allows us to determine all distinct roots by varying 'k', which is essential for solving the given problem.
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