Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles39m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
6. Trigonometric Identities and More Equations
Introduction to Trigonometric Identities
Problem 5.14a
Textbook Question
Textbook QuestionWork each problem.
Given tan x = -5⁄4, where π/2< x < π, use the trigonometric identities to find cot x, csc x and sec x.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Trigonometric Identities
Trigonometric identities are equations that involve trigonometric functions and are true for all values of the variables involved. Key identities include the Pythagorean identity, reciprocal identities, and quotient identities. These identities allow us to express one trigonometric function in terms of another, which is essential for solving problems involving angles and their relationships.
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Quadrants and Signs of Trigonometric Functions
The unit circle divides the coordinate plane into four quadrants, each with specific signs for sine, cosine, and tangent functions. In the second quadrant (where π/2 < x < π), sine is positive while cosine and tangent are negative. Understanding the signs of these functions in different quadrants is crucial for determining the values of cotangent, cosecant, and secant when given a specific tangent value.
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Reciprocal Trigonometric Functions
Reciprocal trigonometric functions are derived from the primary trigonometric functions. For example, cosecant (csc) is the reciprocal of sine, secant (sec) is the reciprocal of cosine, and cotangent (cot) is the reciprocal of tangent. Knowing these relationships allows us to easily compute the values of these functions once we have the value of tangent, as in this problem.
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