Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles39m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
2. Trigonometric Functions on Right Triangles
Trigonometric Functions on Right Triangles
1:51 minutes
Problem 9
Textbook Question
Textbook QuestionIn Exercises 9–16, use the given triangles to evaluate each expression. If necessary, express the value without a square root in the denominator by rationalizing the denominator.
cos 30°
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Trigonometric Ratios
Trigonometric ratios are relationships between the angles and sides of a right triangle. The primary ratios include sine, cosine, and tangent, defined as the ratios of the lengths of the sides opposite, adjacent, and hypotenuse to a given angle. For example, in triangle PQR, cos(30°) is calculated as the length of the adjacent side (QR) over the hypotenuse (PR).
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Special Right Triangles
Special right triangles, specifically the 30-60-90 triangle, have known side ratios that simplify calculations. In a 30-60-90 triangle, the sides opposite the 30°, 60°, and 90° angles are in the ratio 1:√3:2. This means that if the shortest side is 1, the longer leg is √3, and the hypotenuse is 2, making it easier to find trigonometric values without complex calculations.
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Rationalizing the Denominator
Rationalizing the denominator is a process used to eliminate square roots or irrational numbers from the denominator of a fraction. This is often done by multiplying the numerator and denominator by a suitable value that will result in a rational number in the denominator. For example, if the expression involves a square root in the denominator, multiplying by that square root can help simplify the expression.
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