Table of contents
- 0. Review of College Algebra4h 43m
- 1. Measuring Angles39m
- 2. Trigonometric Functions on Right Triangles2h 5m
- 3. Unit Circle1h 19m
- 4. Graphing Trigonometric Functions1h 19m
- 5. Inverse Trigonometric Functions and Basic Trigonometric Equations1h 41m
- 6. Trigonometric Identities and More Equations2h 34m
- 7. Non-Right Triangles1h 38m
- 8. Vectors2h 25m
- 9. Polar Equations2h 5m
- 10. Parametric Equations1h 6m
- 11. Graphing Complex Numbers1h 7m
8. Vectors
Geometric Vectors
Problem 7.18
Textbook Question
Textbook QuestionVector v has the given direction angle and magnitude. Find the horizontal and vertical components.
θ = 27° 30' |v| = 15.4
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Direction Angle
The direction angle of a vector is the angle formed between the positive x-axis and the line representing the vector. It is typically measured in degrees or radians and indicates the orientation of the vector in a two-dimensional plane. In this case, the angle θ = 27° 30' specifies how the vector is inclined relative to the horizontal axis.
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Magnitude of a Vector
The magnitude of a vector represents its length or size, denoted as |v|. It is a scalar quantity that indicates how far the vector extends from the origin to its endpoint. In this problem, the magnitude is given as 15.4, which is essential for calculating the horizontal and vertical components of the vector.
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Horizontal and Vertical Components
The horizontal (x) and vertical (y) components of a vector can be found using trigonometric functions. Specifically, the horizontal component is calculated as |v| * cos(θ) and the vertical component as |v| * sin(θ). These components allow us to express the vector in terms of its influence along the x and y axes, facilitating further analysis and calculations.
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