Precalculus
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Change the following exponential expression to its equivalent logarithmic form.
3x=73^{x}=73x=7
log37=x\log_37=xlog37=x
log73=x\log_73=xlog73=x
log3x=7\log_3x=7log3x=7
log7=3x\log7=3^{x}log7=3x