Precalculus
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Find the domain of the rational function. Then, write it in lowest terms.
f(x)=x2+9x−3f\left(x\right)=\frac{x^2+9}{x-3}f(x)=x−3x2+9
{x∣x≠0}, f(x)=1x−3f\left(x\right)=\frac{1}{x-3}f(x)=x−31
{x∣x≠3}, f(x)=x2+9x−3f\left(x\right)=\frac{x^2+9}{x-3}f(x)=x−3x2+9
{x∣x≠−3}, f(x)=x2+9x−3f\left(x\right)=\frac{x^2+9}{x-3}f(x)=x−3x2+9
{x∣x≠3}, f(x)=x+3f\left(x\right)=x+3f(x)=x+3