10:24Electric Field (2 of 3) Calculating the Magnitude and Direction of the Electric FieldStep by Step Science381views
Multiple ChoiceA 1.5μC charge, with a mass of 50g, is in the presence of an electric field that perfectly balances its gravity. What magnitude does the electric field need to be, and in what direction does it need to point?1089views23rank5commentsHas a video solution.
Multiple ChoiceIf two equal charges are separated by some distance, they form an electric dipole. Find the electric field at the center of an electric dipole, given by the point P in the following figure, formed by a 1C and a −1C charge separated by 1 cm.1282views18rank9commentsHas a video solution.
Multiple Choice4 charges are arranged as shown in the following figure. Find the magnitude of the electric field at the center of the arrangement, indicated by the point P.1596views21rank12commentsHas a video solution.
Multiple ChoiceIn the following figure, a mass m is balanced such that its tether is perfectly horizontal. If the mass is m and the angle of the electric field is θ, what is the magnitude of the electric field, E, expressed in terms of m, q, and θ?716views13rank2commentsHas a video solution.
Multiple ChoiceA 1.2g plastic bead is given a charge of −14 nC by rubbing. What magnitude and direction of electric field is necessary to levitate the bead?263views
Textbook QuestionTwo positive point charges q are placed on the x-axis, one at x = a and one at x = -a. (a) Find the magnitude and direction of the electric field at x = 0.940viewsHas a video solution.
Textbook QuestionA +8.75-mC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50-mC point charge by a light, nonconducting 2.50-cm wire. A uniform electric field of magnitude 1.85 * 10^8 N/C is directed parallel to the wire, as shown in Fig. E21.34. (b) What would the tension be if both charges were negative?933viewsHas a video solution.
Textbook QuestionA +8.75-mC point charge is glued down on a horizontal frictionless table. It is tied to a -6.50-mC point charge by a light, nonconducting 2.50-cm wire. A uniform electric field of magnitude 1.85 * 10^8 N/C is directed parallel to the wire, as shown in Fig. E21.34. (a) Find the tension in the wire.294viewsHas a video solution.
Textbook QuestionA very long, straight wire has charge per unit length 3.20 * 10^-10 C/m. At what distance from the wire is the electricfield magnitude equal to 2.50 N/C?1334viewsHas a video solution.
Textbook QuestionA point charge is placed at each corner of a square with side length a. All charges have magnitude q. Two of the charges are positive and two are negative (Fig. E21.42). What is the direction of the net electric field at the center of the square due to the four charges, and what is its magnitude in terms of q and a?156viewsHas a video solution.
Textbook QuestionA 10.0 nC charge is located at position (x, y)=(1.0 cm, 2.0 cm). At what (x, y) position(s) is the electric field c. (21,600 î−28,800ĵ) N/C?215viewsHas a video solution.
Textbook QuestionA small 1.0 g block charged to 75 nC is placed on a 30° inclined plane. The coefficients of static and kinetic friction are 0.20 and 0.10, respectively. What minimum strength horizontal electric field is needed to keep the block from sliding down the plane?369views1rankHas a video solution.
Textbook QuestionAn electric field E=200,000î N/C causes the point charge in FIGURE P22.68 to hang at an angle. What is θ?404views1rankHas a video solution.
Textbook QuestionA 0.10 g honeybee acquires a charge of +23 pC while flying. b. What electric field (strength and direction) would allow the bee to hang suspended in the air?108viewsHas a video solution.
Textbook QuestionA −12 nC charge is located at (x, y)=(1.0 cm, 0 cm). What are the electric fields at the positions (x, y)=(5.0 cm, 0 cm), (−5.0 cm, 0 cm), and (0 cm, 5.0 cm)? Write each electric field vector in component form.159viewsHas a video solution.
Textbook QuestionA −15 nC charge is at x=+2.0 cm on the x-axis. A second charge q is located somewhere on the x-axis to the left of the origin. The electric field at y=2.0 cm on the y-axis is Ē =3.0×105 î N/C . What are (a) the charge q in nC and (b) its distance from the origin?111viewsHas a video solution.
Textbook QuestionA thin, horizontal, 10-cm-diameter copper plate is charged to 3.5 nC. If the charge is uniformly distributed on the surface, what are the strength and direction of the electric field (a) 0.1 mm above the center of the top surface of the plate?55viewsHas a video solution.
Textbook QuestionCALC Charge Q is uniformly distributed along a thin, flexible rod of length L. The rod is then bent into the semicircle shown in FIGURE P23.48. a. Find an expression for the electric field Ē at the center of the semicircle. Hint: A small piece of arc length Δs spans a small angle Δθ=Δs/R , where R is the radius.41viewsHas a video solution.
Textbook QuestionFIGURE P23.41 is a cross section of two infinite lines of charge that extend out of the page. Both have linear charge density λ. Find an expression for the electric field strength E at height y above the midpoint between the lines.31views
Textbook QuestionTwo 10-cm-diameter charged disks face each other, 20 cm apart. The left disk is charged to −50 nC and the right disk is charged to +50 nC. a. What is the electric field Ē, both magnitude and direction, at the midpoint between the two disks?20views
Textbook QuestionConsider an oil droplet of mass m and charge q. We want to determine the charge on the droplet in a Millikan-type experiment. We will do this in several steps. Assume, for simplicity, that the charge is positive and that the electric field between the plates points upward. (c) A spherical object of radius r moving slowly through the air is known to experience a retarding force Fₔᵣₐ₉ = −6πηr v where η is the viscosity of the air. Use this and your answer to part b to show that a spherical droplet of density ρ falling with a terminal velocity vₜₑᵣₘ has a radius . r = √9ηvₜₑᵣₘ / 2pg325viewsHas a video solution.
Textbook QuestionThe identical small spheres shown in FIGURE P22.64 are charged to +100 nC and −100 nC. They hang as shown in a 100,000 N/C electric field. What is the mass of each sphere?567viewsHas a video solution.
Textbook QuestionAn electret is similar to a magnet, but rather than being permanently magnetized, it has a permanent electric dipole moment. Suppose a small electret with electric dipole moment 1.0×10^−7 C m is 25 cm from a small ball charged to +25 nC , with the ball on the axis of the electric dipole. What is the magnitude of the electric force on the ball?381viewsHas a video solution.
Textbook QuestionA point charge q1 = -4.00 nC is at the point x = 0.600 m, y = 0.800 m, and a second point charge q2 = +6.00 nC is at the point x = 0.600 m, y = 0. Calculate the magnitude and direction of the net electric field at the origin due to these two point charges.2383viewsHas a video solution.
Textbook QuestionA -4.00-nC point charge is at the origin, and a second -5.00-nC point charge is on the x-axis at x = 0.800 m. (a) Find the electric field (magnitude and direction) at each of the following points on the x-axis: (i) x = 0.200 m; (ii) x = 1.20 m; (iii) x = -0.200 m. (b) Find the net electric force that the two charges would exert on an electron placed at each point in part (a).882viewsHas a video solution.
Textbook Question(a) Calculate the magnitude and direction (relative to the +x-axis) of the electric field in Example 21.6. Example 21.6: A point charge q = -8.0 nC is located at the origin. Find the electric-field vector at the field point x = 1.2 m, y = -1.6 m.261viewsHas a video solution.
Textbook QuestionElectric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (a) What magnitude and sign of charge would a 60-kg human have to acquire to overcome his or her weight by the force exerted by the earth's electric field?718viewsHas a video solution.
Textbook QuestionElectric Field of the Earth. The earth has a net electric charge that causes a field at points near its surface equal to 150 N/C and directed in toward the center of the earth. (b) What would be the force of repulsion between two people each with the charge calculated in part (a) and separated by a distance of 100 m? Is use of the earth's electric field a feasible means of flight? Why or why not?212viewsHas a video solution.
Textbook QuestionA charge of -6.50 nC is spread uniformly over the surface of one face of a nonconducting disk of radius 1.25 cm. (d) Why is the field in part (a) stronger than the field in part (b)? Why is the field in part (c) the strongest of the three fields?206viewsHas a video solution.
Textbook QuestionThe electric field at a point in space is E =(400î+100jˆ) N/C. a. What is the electric force on a proton at this point? Give your answer in component form.164viewsHas a video solution.
Textbook QuestionThe nuclei of large atoms, such as uranium, with 92 protons, can be modeled as spherically symmetric spheres of charge. The radius of the uranium nucleus is approximately 7.4×10−15 m. (b) What magnitude of electric field does it produce at the distance of the electrons, which is about 1.0×10−10 m?355viewsHas a video solution.
Textbook QuestionA Van de Graaff generator is a device for generating a large electric potential by building up charge on a hollow metal sphere. A typical classroom-demonstration model has a diameter of 30 cm. b. What is the electric field strength just outside the surface of the sphere when it is charged to 500,000 V?21viewsHas a video solution.
Textbook QuestionWhat are the strength and direction of the electric field 1.0 mm from (a) a proton and93viewsHas a video solution.
Textbook QuestionA hollow copper sphere has inner radius 1.0 cm and outer radius 2.5 cm. A 5.0 A current flows radially outward from the inner surface to the outer surface. What is the electric field strength at r=2.0 cm?148viewsHas a video solution.